Question

Calculate the d-spacing (in nm) of a solid for X-ray radiation with λ = 2.5 Å and incident angle of θ = 26°. In the equation for Bragg's Law, assume that n = 1. Report your answer to 2 significant figures.

A) 1.0 nm
B) 0.9 nm
C) 1.1 nm
D) 2.0 nm

Answer 1

The d-spacing of the solid is approximately 0.91 nm.

Step-by-step explanation:

The distance between the planes in a solid can be calculated using Bragg's law, which is given by the equation nλ = 2d sin θ, where n is the order of the diffraction, λ is the wavelength of the X-ray radiation, d is the d-spacing, and θ is the incident angle.

For this question, n = 1, λ = 2.5 Å (or 0.25 nm), and θ = 26°. Plugging these values into the equation, we can solve for d:

d = λ / (2 sin θ) = 0.25 nm / (2 sin 26°) ≈ 0.91 nm

Therefore, the d-spacing of the solid is approximately 0.91 nm.