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Find the Jacobian of the transformation.

x = 2u⁶v, y = 4u⁸v
a) 8u⁵v
b) 12u⁷v
c) 16u⁷v
d) 24u¹1v

User Jemshit
by
8.3k points

1 Answer

1 vote

Final answer:

The Jacobian of the transformation with x = 2u⁶v and y = 4u⁸v is -16u¹³v, which indicates a scaling of areas in the u-v plane when transformed to the x-y plane. The provided options do not include the correct answer, suggesting a possible error or typo in the provided choices.

Step-by-step explanation:

The Jacobian of a transformation is a determinant that gives us a measure of the change of variables in a multiple integral. When dealing with a Jacobian for a transformation from variables (u, v) to (x, y), where x and y are defined as x = 2u⁶v and y = 4u⁸v, we need to construct a matrix with the partial derivatives of x and y with respect to u and v and then calculate the determinant of this matrix.

The matrix for the Jacobian is:

  • ∂x/∂u = 12u⁵v
  • ∂x/∂v = 2u⁶
  • ∂y/∂u = 32u⁷v
  • ∂y/∂v = 4u⁸

Calculating the determinant of this matrix gives us:

J = (∂x/∂u)(∂y/∂v) - (∂x/∂v)(∂y/∂u) = (12u⁵v × 4u⁸) - (2u⁶ × 32u⁷v) = 48u¹³v - 64u¹³v = -16u¹³v.

Therefore, the Jacobian is -16u¹³v, which is not present in options a), b), c), or d). Therefore, it appears there may be a typo within the provided choices since the correct Jacobian is not listed.

User AntBrown
by
8.0k points
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