Final answer:
The partial pressure of argon in atm is calculated by dividing 7.10 mmHg by 760 mmHg/atm, which gives 0.00934 atm. Since mmHg and torr are equivalent, the pressure in torr remains 7.10.
Therefore the correct answer is thus option (b): 0.00934 atm and 7.10 torr.
Step-by-step explanation:
The student needs to convert the partial pressure of argon from mmHg to atm and to torr. Using the conversion factor between millimeters of mercury (mmHg) and atmospheres (atm), we know that 1 atm equals 760 mmHg. To convert 7.10 mmHg to atm, divide 7.10 mmHg by 760 mmHg/atm. This gives a result in atm which should be displayed in scientific notation if required.
To convert the pressure to torr, it's important to note that mmHg and torr are equivalent units, so the pressure in torr will remain the same as in mmHg. Therefore, the partial pressure of argon in torr is 7.10 torr.
The correct answer is thus option (b): 0.00934 atm and 7.10 torr, when rounded to three significant digits.