Question

An inductor with an inductance of 2.30 H and a resistance of 8.00 Ω is connected to a battery with an EMF of 6.50 V and negligible internal resistance. What is the current flowing through the circuit?

a) 0.81 A
b) 0.68 A
c) 0.64 A
d) 0.72 A

Answer 1

Using Ohm's Law and the given values for EMF and resistance, the current flowing through the circuit is calculated to be 0.81 A.

Step-by-step explanation:

The student's question pertains to the calculation of the current flowing through a circuit that includes an inductor and a resistor.

Given the values of inductance (2.30 H), resistance (8.00 Ω), and electromotive force (EMF) (6.50 V), and assuming that the effect of the inductor's inductance on the current is instantaneous (which is true in a DC circuit once the current has stabilized), we can use Ohm's Law to find the current flowing through the circuit. Ohm's Law states that V = IR, where V is the voltage, I is the current, and R is the resistance.

By rearranging the formula, we get I = V / R. We can plug the given values into the formula to find the current: I = 6.50 V / 8.00 Ω = 0.8125 A. This value should be rounded according to the significant figures of the given data, which leads us to 0.81 A. Therefore, answer (a) 0.81 A is the correct choice.