Question

What is the molarity of chloride ions in a 1.0 L solution containing 50.0 g of magnesium chloride? (MgCl₂ molar mass = 95.21 g/mol)

Answer 1

The molarity of chloride ions in the 1.0 L solution containing 50.0 g of magnesium chloride is 1.05 M.

Step-by-step explanation:

To find the molarity of chloride ions in the solution, we need to first calculate the number of moles of magnesium chloride in the 50.0 g sample. We can use the molar mass of MgCl₂ to do this:

Molar mass of MgCl₂ = 95.21 g/mol

Number of moles = (50.0 g) / (95.21 g/mol) = 0.525 moles

Since one mole of MgCl₂ produces two moles of chloride ions (Cl⁻), the molarity of chloride ions in the solution is:

Molarity of chloride ions = (0.525 moles MgCl₂) x (2 mol Cl⁻ / 1 mol MgCl₂) / (1.0 L) = 1.05 M