Final answer:
To synthesize 14.0 mol of NO, approximately 283.2 L of O2 at 760. mmHg and 29 °C is required.
Step-by-step explanation:
To determine the volume of O2 required to synthesize 14.0 mol of NO, we can use the ideal gas law equation, PV = nRT. Given that the pressure is 760. mmHg, the temperature is 29 °C (which needs to be converted to Kelvin), and the number of moles is 14.0 mol, we can solve for the volume. First, we need to convert the temperature to Kelvin by adding 273.15 to 29 °C, which gives us 302.15 K. Next, we'll substitute the values into the equation: (760. mmHg)(V) = (14.0 mol)(0.0821 L·atm/(mol·K))(302.15 K). Solving for V, we find that the volume of O2 required is approximately 283.2 L.