Final answer:
To melt 50.0 grams of ice at 0°C, 16700 joules of heat are required. This value is obtained by multiplying the mass of the ice by the heat of fusion of ice, which is 334 J/g.
Step-by-step explanation:
The amount of heat required to melt 50.0 grams of ice at 0°C can be calculated using the heat of fusion for water, which is the amount of energy needed to change a substance from the solid phase to the liquid phase at its melting point. The heat of fusion of ice is 334 J/g. By multiplying the mass of the ice (50.0 grams) by the heat of fusion, we can find the total amount of heat energy necessary for the melting process.
The calculation is as follows:
Q = m × Lf = 50.0 g × 334 J/g = 16700 J
Therefore, 16700 joules of heat are required to melt 50.0 grams of ice at 0°C.
To calculate the amount of heat required to melt 50.0 grams of ice at 0°C, we need to use the equation Q = mLf, where Q is the heat transferred, m is the mass of the ice, and Lf is the heat of fusion of ice.
Given that the heat of fusion of ice is 79.9 cal/g, we can convert it to joules by multiplying it by 4.18 J/cal. So, Lf = 79.9 cal/g x 4.18 J/cal = 333.56 J/g.
Now we can calculate the heat required: Q = 50.0 g x 333.56 J/g = 16680 J.