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what is the cross-sectional area of a cement pipe 4 in. thick with an inner diameter of 1 ft? use pi= 3.14.

User Zahra
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Final answer:

The cross-sectional area of the cement pipe is approximately 113.04 square inches. Cross-sectional area of cement pipe with 6-inch radius ≈ 113.04 square inches, using A = πr².

Step-by-step explanation:

The cross-sectional area of a cement pipe can be found using the formula A = πr², where A is the cross-sectional area and r is the radius of the pipe. In this case, the inner diameter of the pipe is given as 1 ft, which is equivalent to a radius of 0.5 ft or 6 inches. Converting the radius to inches, we get r = 6 inches. Substituting this value into the formula, we have A = 3.14 × (6 inches)².

Squaring the radius, we get A = 3.14 × 36 square inches.

Multiplying, we get A ≈ 113.04 square inches.

The cross-sectional area of a cement pipe is calculated using the formula A = pi r² where A is the area and r is the radius. Given the inner diameter of the pipe as 1 ft, the radius is (0.5) ft or 6 inches. Converting to inches, r = 6 inches. Substituting into the formula, A = 3.14 × (6inches)², simplifying to A = 3.14 × 36 square inches. The result is approximately 113.04 square inches, representing the pipe's cross-sectional area. This calculation is fundamental for engineering and construction purposes, ensuring accurate assessments of pipe dimensions for various applications.

User Andrei Goldmann
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