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What is Kₛp for PbCrO₄ if its solubility is 4.2×10^–5 g/L?

a) 1.68×10^–20
b) 2.5×10^–6
c) 1.2×10^–10
d) 8.4×10^–15

User Trogper
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1 Answer

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Final answer:

The solubility product constant (Ksp) for PbCrO4 is 4.2×10–5.

Step-by-step explanation:

The solubility product constant (Ksp) can be calculated using the molar solubility of a compound. In this case, the molar solubility of PbCrO4 is given as 4.2×10–5 g/L. Since the stoichiometry of the dissolution reaction shows a 1:1 relation between the molar amounts of compound and its two ions, both [Pb2+] and [CrO42-] are equal to the molar solubility of PbCrO4. Therefore, the value of Ksp for PbCrO4 is 4.2×10–5.

User DejaVuSansMono
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