Final answer:
To find the last number in the sequence that starts with 2 and counts by 3s until reaching 449, the last number is 449.
Step-by-step explanation:
To find the last number in the sequence that starts with 2 and counts by 3s until reaching 449, we need to determine how many times we can add 3 to 2 until we reach or exceed 449. We can set up an equation: 2 + 3x = 449, where x represents the number of times we add 3. To solve for x, we subtract 2 from both sides of the equation: 3x = 447. Then, we divide both sides by 3 to isolate x: x = 447 ÷ 3. Simplifying, we find that x = 149.
Since we are counting from 2 and adding 3 a total of 149 times, the last number in the sequence would be: 2 + 3(149) = 2 + 447 = 449.