Final answer:
To melt 450 g of ice, 150.3 kJ of heat is absorbed. This is calculated using the latent heat of fusion for water, which is 334 kJ/kg, by multiplying it by the mass of the ice in kilograms.
Step-by-step explanation:
The question is asking how much heat is gained or lost when 450 g of ice melts. The heat required to melt ice is known as the latent heat of fusion. For water, the latent heat of fusion is 334 kJ/kg. To find the total heat (Q) absorbed during the melting process, use the formula:
Q = m x Lf
where:
- m = mass of ice (in this case, 0.450 kg, since 450 g is equivalent to 0.450 kg)
- Lf = latent heat of fusion for water (334 kJ/kg)
Applying this:
Q = 0.450 kg x 334 kJ/kg = 150.3 kJ
Therefore, 450 g of ice absorbs 150.3 kilojoules of heat to melt completely.