Final answer:
The primary topic of the question is the calculation of the final temperature of copper and water when mixed in an a. isolated system, using the concept of heat transfer and the specific heat formula to find thermal equilibrium.
Step-by-step explanation:
The question involves calculating the final temperature of a mixture involving a hot copper part and cool liquid water. This is an application of the principles of thermodynamics, specifically the concept of heat transfer. Since both substances are assumed to be part of an isolated system, the heat lost by the copper part will equal the heat gained by the water until they reach thermal equilibrium. To solve this problem, one must apply the specific heat formula to determine the final temperature that both the copper and water reach when thermal equilibrium is achieved.
The specific heat capacity of copper and water, along with their respective masses and initial temperatures, will be needed. The formula is given by Q = mc∆T, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ∆T is the change in temperature. For an isolated system, the heat gained by one part is the heat lost by the other: Qlost = -Qgained.