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A gas mixture contains RN, Ne, and H₂. What is the total pressure of the mixture, if the mole fraction of H₂ is 0.350 and the partial pressure of H₂ is 0.280 atm?

a. 0.175 atm
b. 0.280 atm
c. 0.350 atm
d. 0.630 atm

User Knarz
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1 Answer

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Final answer:

The total pressure of a gas mixture with a mole fraction of H₂ at 0.350 and its partial pressure at 0.280 atm is calculated as 0.800 atm. This is based on the relationship Ptotal = P / X. However, this calculated pressure is not an option listed in the question, suggesting a potential typo.

Step-by-step explanation:

The student asked for the total pressure of a gas mixture containing RN, Ne, and H₂ when the mole fraction of H₂ is 0.350 and the partial pressure of H₂ is 0.280 atm.

To find the total pressure of the mixture, we use the relationship between mole fraction (X) and partial pressure (P) which is expressed in the equation P = X × Ptotal. The partial pressure of a gas is the pressure it would exert if it alone occupied the volume of the mixture at the same temperature. To find the total pressure (Ptotal), we rearrange the equation to Ptotal = P / X. We can apply this formula directly using the provided fraction and partial pressure of H₂.

Ptotal = PH₂ / XH₂ = 0.280 atm / 0.350 = 0.800 atm

Therefore, the total pressure of the gas mixture is 0.800 atm. However, this option is not provided in the question, and this may be an indication of a typo in the question or in the provided answer options. In such cases, it's important to recheck the calculations and verify the data provided in the question.

User Amol Sharma
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