Question

Reacting 3.00 mol of nitrogen gas with 6.00 mol of hydrogen gas will produce how many moles of ammonia according to the following balanced chemical equation? N2(g) + 3H2(g) → 2NH3(g)

a) 1.00 mol
b) 2.00 mol
c) 3.00 mol
d) 4.50 mol

Answer 1

When 3.00 mol of nitrogen gas reacts with 6.00 mol of hydrogen gas, 4.00 mol of ammonia is produced according to the chemical equation.

Step-by-step explanation:

Reacting 3.00 mol of nitrogen gas with 6.00 mol of hydrogen gas will produce 4.00 mol of ammonia according to the balanced chemical equation: N2(g) + 3H2(g) → 2NH3(g). You can see this by following the chemical equation coefficients, which imply that for every 1 mol of nitrogen, you need 3 mol of hydrogen to produce 2 mol of ammonia. Since you have twice as much hydrogen as needed for the 3.00 mol of nitrogen (2 x 3 mol of hydrogen to react with nitrogen), the reaction will produce twice the amount of ammonia indicated by the equation coefficients, meaning 2 x 2 mol of ammonia.