Final answer:
The oxidation state of Co in Co(H₂O)₃(NH₃)₃Cl₃ is +3, and the d electron count is 7.
Step-by-step explanation:
The oxidation state of Co in Co(H₂O)₃(NH₃)₃Cl₃ is +3.
To determine the d electron count, we need to consider the oxidation state of Co and its coordination number. The coordination number of Co in this complex is 6, which means there are six ligands surrounding the central Co ion.
Since the oxidation state of Co is +3, we can determine the d electron count using the formula: d electron count = 3 - oxidation state. Therefore, the d electron count of Co in Co(H₂O)₃(NH₃)₃Cl₃ is 7.