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A 2 kg object is moving to the right with a speed of 1 m/s when it experiences an impulse of 4 N s. What is the object’s speed and direction after the impulse?

a) 3 m/s, right
b) 1 m/s, left
c) 2 m/s, right
d) 4 m/s, left

User Meaningqo
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1 Answer

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Final answer:

The final velocity of the 2 kg object after experiencing a 4 N s impulse is 3 m/s to the right. The impulse increases the object's momentum which leads to an increase in velocity, without changing the direction of motion. Therefore, the correct answer is a) 3 m/s, right.

Step-by-step explanation:

The student is asked to determine the final velocity of a 2 kg object after it experiences an impulse of 4 N s. Initially, the object is moving to the right with a velocity of 1 m/s. Impulse is equal to change in momentum, and in this case can be calculated using the formula Impulse = Change in momentum = Final momentum - Initial momentum.

The initial momentum of the object is mass × velocity = 2 kg × 1 m/s = 2 kg·m/s. Applying the impulse of 4 N s, which increases the object's momentum in the same direction of motion (since direction is not specified as changing), the total final momentum is initial momentum + impulse = 2 kg·m/s + 4 kg·m/s = 6 kg·m/s.

Now, to find the final velocity, we divide the new momentum by the mass of the object. Final velocity = Final momentum / Mass = 6 kg·m/s / 2 kg = 3 m/s. Therefore, the object will be moving to the right at 3 m/s after the impulse. The correct answer is (a) 3 m/s, right.

User Peter Lewis
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