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An object is released from rest near the surface of a planet. What distance does the object fall 10 seconds after it is released from rest?

a. 490 m
b. 500 m
c. 550 m
d. 980 m

User Nilskp
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1 Answer

4 votes

Final answer:

When an object is released from rest near the surface of a planet, it falls under the influence of gravity. The distance the object falls can be calculated using the formula d = (1/2) * g * t^2. Hence, the correct answer is option (a) 490m.

Step-by-step explanation:

When an object is released from rest near the surface of a planet, it falls under the influence of gravity. The distance the object falls can be calculated using the formula:

d = (1/2) * g * t^2

Where d is the distance, g is the acceleration due to gravity, and t is the time. In this case, the object falls for 10 seconds, so we can plug in the values and calculate:

d = (1/2) * 9.8 * (10)^2 = 490 m

Therefore, the correct answer is a. 490 m.

User JamesM
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