The equation in slope-intercept form for the line with y-intercept -1 and slope -4/3 is y = -4/3x - 1
How to write an equation in slope-intercept form for the line
From the question, we have the following parameters that can be used in our computation:
y-intercept −1 and slope -4/3
This means that the line passes through the point (0, -1) and has a slope of -4/3.
The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
Substituting the given values of m and b into the slope-intercept form, we get:
y = -4/3x - 1
The graph is attached