Final Answer:
If the party host can bring 20 children to the indoor playground, and there are two parties in total, then the staff can let in an additional 40 children, allowing for a total of 60 children in the play center. Therefore, the correct answer is option c, 40.
Explanation:
Given that each party host can bring 20 children to the indoor playground and there are two parties in total, we can calculate the total capacity by multiplying the number of children per party by the total number of parties.
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. Since the staff can accommodate an additional 40 children after considering the 20 children per party, the total number of additional children allowed in the play center is 40. Therefore, the staff can let in 40 more children to the play center, bringing the total capacity to 60 children (20 children from each of the two parties plus the additional 40 children). This calculation ensures the staff maintains a safe and manageable environment while accommodating the additional children based on the two parties in the play center.
Understanding the capacity constraints and total number of children allowed based on the parties' count is crucial in managing the indoor playground's occupancy. By considering the fixed number of children each party can bring and multiplying it by the total number of parties, we arrive at the maximum capacity occupied by the parties, which is 40 children. The staff's ability to accommodate an additional 40 children ensures the play center remains within its total capacity limit of 60 children, maintaining a balanced and enjoyable experience for all children attending the two parties.