Question

Tickets for a school event were $1.75 for students and $3.25 for parents. If a total of 80 tickets were sold for $185.00, how many student and parent tickets were sold? There were ________student tickets sold and ______ parent tickets sold.

Answer 1

To solve this problem, we can use a system of equations. Let's define the number of student tickets as 's' and the number of parent tickets as 'p'. We can set up the following equations: 1.75s + 3.25p = 185 (Total value of tickets sold) and s + p = 80 (Total number of tickets sold). Solving this system of equations gives us 50 student tickets sold and 30 parent tickets sold.

Step-by-step explanation:

To solve this problem, we can use a system of equations.

Let's define the number of student tickets as 's' and the number of parent tickets as 'p'.

We can set up the following equations:

1.75s + 3.25p = 185 (Total value of tickets sold)

s + p = 80 (Total number of tickets sold)

Now we can solve this system of equations using substitution or elimination.

If we choose to solve by substitution, we can solve the second equation for s:

s = 80 - p

Substituting this value of s into the first equation:

1.75(80 - p) + 3.25p = 185

Simplifying the equation: 140 - 1.75p + 3.25p = 185

Combining like terms: 140 + 1.50p = 185

Subtracting 140 from both sides: 1.50p = 45

Dividing both sides by 1.50: p = 30

Now substituting this value of p back into the second equation to find s:

s + 30 = 80

Subtracting 30 from both sides: s = 50

Therefore, 50 student tickets were sold and 30 parent tickets were sold.