Question

When 308.3 mL of 4.78 M HNO₃ is allowed to react with Al.

A) Calculate the moles of HNO₃
B) Identify the limiting reactant
C) Calculate the moles of Al
D) None of the above

Answer 1

The number of moles of HNO3 is calculated to be 1.4747 mol using the volume and molarity of the solution. Identifying the limiting reactant and calculating the moles of Al requires additional information.

Step-by-step explanation:

To calculate the number of moles of HNO3 in a solution with a volume of 308.3 mL (or 0.3083 L) and a concentration of 4.78 M, we use the equation:

moles of HNO3 = volume in liters × concentration in molarity

Therefore, the number of moles of HNO3 is:

moles HNO3 = 0.3083 L × 4.78 M = 1.4747 mol HNO3

Without information on the mass or moles of Al, we cannot identify the limiting reactant or calculate the moles of Al.