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A rectangular dam is 98 ft long and 50 ft high. If the water is 40 ft deep, find the force of the water on the dam (the density of water is 62.4 lb/ft³).

A. 2,457,600 lb

B. 1,228,800 lb

C. 614,400 lb

D. 307,200 lb

User Jlavallet
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1 Answer

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Final answer:

The force of the water on the dam is approximately 2,457,600 lb.

Step-by-step explanation:

In this problem, we can calculate the force on the dam using the formula F = pgh²L/2, where p is the density of water, h is the depth of the water at the dam, and L is the length of the dam.

To find the force of the water on a dam, we can use the formula F = pgh²L/2, where p represents the density of water, g is the acceleration due to gravity, h is the depth of the water at the dam, and L is the length of the dam. The dam in question has a length of 98 ft, and the water has a depth of 40 ft. Given the density of water is 62.4 lb/ft³, the force exerted on the dam is calculated as follows:

Given that the density of water is 62.4 lb/ft³, the depth is 40 ft, and the length is 98 ft, we can substitute these values into the formula:

F = (62.4 lb/ft³) × (40 ft)² × (98 ft) / 2

Calculating this gives us F ≈ 2,457,600 lb.

Therefore, the force of the water on the dam is approximately 2,457,600 lb (Option A).

User Salmanbw
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