Final answer:
The temperature of an 11.2-L sample of carbon monoxide that expands to 13.3 L at 55 °C and 744 torr, when recalculated for the original volume, is approximately 274.7 Kelvin. The closest answer choice is C. 276 K.
Step-by-step explanation:
To determine the temperature of an 11.2-L sample of carbon monoxide (CO) at 744 torr, which expands to 13.3 L at 55 °C and the same pressure, we can use the Combined Gas Law. The Combined Gas Law relates pressure, volume, and temperature of a given amount of gas as long as the amount of gas and the pressure remain constant. The equation is expressed as: (P1 x V1) / T1 = (P2 x V2) / T2, where P stands for pressure, V for volume, and T for temperature in Kelvin.
Since the pressure and the amount of gas remain constant in this scenario, we can simplify the equation to V1 / T1 = V2 / T2. Rearranging the formula to solve for T1, we get T1 = (V1 x T2) / V2. First, convert the temperature of 55 °C to Kelvin by adding 273.15, which equals 328.15 K. Then plug in the values:
T1 = (11.2 L x 328.15 K) / 13.3 L = 274.7 K.
So the temperature of the 11.2-L sample of CO, when expanded to 13.3 L at 55 °C and 744 torr, is approximately 274.7 K. Therefore, the closest answer from the options provided is C. 276 K.