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A solution with a pOH of 11.70 has an [H⁺ ] of

A) 3.2×10⁻⁴ M
B) 5.0×10⁻³ M
C) 2.30 M
D) 0.36 M

1 Answer

2 votes

Final answer:

The concentration of hydronium ions [H+] in a solution with a pOH of 11.70 is calculated using the relationship 14.00 = pH + pOH, resulting in [H+] being 5.0 × 10^-3 M.

Step-by-step explanation:

The question asks about the concentration of hydronium ions ([H+]) in a solution with a given pOH. Using the formula that relates pH, pOH, and concentration, 14.00 = pH + pOH, we can find the pH and then calculate the [H+]. Given that the solution has a pOH of 11.70, we can calculate the pH as follows:

  • pH = 14.00 - pOH
  • pH = 14.00 - 11.70
  • pH = 2.30

Now, we can calculate the [H+] using the pH:

  • [H+] = 10-pH
  • [H+] = 10-2.30
  • [H+] = 5.0 × 10-3 M

Therefore, the concentration of hydronium ions in a solution with a pOH of 11.70 is 5.0 × 10-3 M, which corresponds to option B.

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