Question

two group of hikers left camp at the same time and returned to the camp at the same time. one group hiked 6mph out to the camp and hiked back to the camp at 4mph. the second group hiked at constant speed all day. how fast did second group hike if each group hiked 24 mile

Answer 1

The second group hiked at a constant speed of 4.8 mph to cover the 24-mile round trip in the same 5-hour span as the first group, which hiked out at 6 mph and back at 4 mph.

Step-by-step explanation:

To figure out how fast the second group of hikers traveled if each group hiked 24 miles round trip and returned to camp at the same time, we'll need to use the concept of average speed and the relationship between speed, distance, and time. The first group hiked out at 6 mph and came back at 4 mph, while the second group hiked at a constant speed.

For the first group, we can calculate the time taken for each leg of their journey:

• Time for outbound journey = Distance / Speed = 12 miles / 6 mph = 2 hours.
• Time for return journey = Distance / Speed = 12 miles / 4 mph = 3 hours.

Now we know that the first group spent a total of 5 hours (2 + 3) on their hike.

Since the second group also returned to camp at the same time, they too must have hiked for 5 hours in total. To find their constant speed, we divide the total distance by the total time:

Speed of second group = Total distance / Total time = 24 miles / 5 hours = 4.8 mph.