Final answer:
To heat 125 grams of water from -15°C to 65°C, it would take 41,840 joules of energy. The calculation is based on the specific heat capacity of water, which is 4.184 J/g°C.
Step-by-step explanation:
To calculate the energy required to heat 125 grams of water from -15 degrees Celsius to 65 degrees Celsius, you need to consider the specific heat capacity of water and the total temperature change. The specific heat capacity of water is 4.184 J/g°C. This means to heat 1 g of water by 1°C, you require 4.184 joules of energy.
Since we are heating the water through a temperature change of 80°C (from -15°C to 65°C), we use the equation:
Energy (J) = mass (g) * specific heat capacity (J/g°C) * ΔT (°C)
Substituting the values we get:
Energy (J) = 125g * 4.184 J/g°C * (65°C - (-15°C))
Energy (J) = 125g * 4.184 J/g°C * 80°C
Energy (J) = 125g * 334.72 J/°C
Energy (J) = 41840 J
Therefore, 41,840 joules of energy are required to heat 125 grams of water from -15°C to 65°C.