Question

A saturated solution of Ag2CrO4 has a silver-ion concentration of 1.3 × 10–4M. What is the Ksp of Ag2CrO4?

A) 2.6 × 10^–8
B) 1.3 × 10^–12
C) 1.7 × 10^–10
D) 5.2 × 10^–6

Answer 1

The Ksp (solubility product constant) of Ag2CrO4 can be determined using the given silver-ion concentration. In a saturated solution of Ag2CrO4, the concentration of Ag+ ions is 1.3 x 10^-4 M. The Ksp of Ag2CrO4 is 1.69 x 10^-12, option B.

Step-by-step explanation:

The Ksp (solubility product constant) of Ag2CrO4 can be determined using the given silver-ion concentration. In a saturated solution of Ag2CrO4, the concentration of Ag+ ions is 1.3 x 10^-4 M. Since Ag2CrO4 dissociates into two Ag+ ions and one CrO4^2- ion, the concentration of the CrO4^2- ion is half of the Ag+ ion concentration, which is 6.5 x 10^-5 M. To calculate the Ksp, we can substitute the concentrations into the Ksp expression.

The Ksp expression for Ag2CrO4 is Ksp = [Ag+]^2 [CrO4^2-]. Substituting the given values, we get:

Ksp = (1.3 x 10^-4)^2 * (6.5 x 10^-5)

Ksp = 1.69 x 10^-12

So, the Ksp of Ag2CrO4 is 1.69 x 10^-12, option B.