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A 450gram mass on a spring is oscillating at 1.2Hz

User Ami
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Final answer:

The student's question pertains to finding the additional mass required to change the period of a 0.500-kg mass on a spring from 1.50 seconds to 2.00 seconds, referring to the principles of simple harmonic motion in physics.

Step-by-step explanation:

The question is related to the concept of simple harmonic motion (SHM) in physics, specifically dealing with the period and frequency of oscillations of a mass attached to a spring. The student is asked to determine how much additional mass must be added to a 0.500-kg mass suspended from a spring so that when the mass oscillates, the period changes from 1.50 seconds to 2.00 seconds.

To solve this, one can use the formula for the period of a spring-mass system, T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. By comparing the periods for different masses while keeping the spring constant k the same, we can calculate the mass needed to achieve the new period of oscillation.

User Parnas
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