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Utane (C₄H₁₀) burns in oxygen to form carbon dioxide and water.

A. Write the balanced chemical equation
B. Determine the limiting reactant
C. Calculate the heat of combustion
D. Identify the combustion products

User Hessam
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1 Answer

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Final answer:

The balanced chemical equation for the combustion of butane (C4H10) is 2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(g). Without the amounts of butane and oxygen, the limiting reactant cannot be determined. The heat of combustion requires the enthalpy of formation for butane, CO2, and H2O to calculate, and the combustion products are carbon dioxide (CO2) and water (H2O).

Step-by-step explanation:

To answer your question, let's go step by step:

A. Write the balanced chemical equation

The balanced chemical equation for the combustion of butane (C₄H₁₀) is:

2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(g)

B. Determine the limiting reactant

To determine the limiting reactant, we would need the amounts of both butane and oxygen. As they are not provided, we cannot determine the limiting reactant without additional information.

C. Calculate the heat of combustion

The heat of combustion of butane can be found using its enthalpy of formation (ΔH°f) which is -126 kJ/mol. The calculation requires knowledge of the enthalpies of formation for CO₂ and H₂O as well.

D. Identify the combustion products

The combustion products are carbon dioxide (CO₂) and water (H₂O), as indicated in the balanced chemical equation.

User Ejima
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