Final answer:
The Physics question asks about the fraction of electrons removed from a ball of copper with a given mass and net charge. By calculating the total number of copper atoms and their initial electrons, and comparing to the net charge in terms of electron count, we can determine the fraction of electrons removed. Option B is correct.
Step-by-step explanation:
The subject of this question is Physics, specifically relating to the concept of charge and the number of electrons in a substance. The net charge on an object indicates whether electrons have been added to or removed from an object. To find the fraction of electrons removed from the copper ball, we would need to know the number of copper atoms present and the total number of electrons that would correspond to the given net charge.
We can calculate the number of copper atoms by using the atomic mass of copper and Avogadro's number. Once we have the number of atoms, we can multiply that by the number of electrons in each copper atom (which is equal to its atomic number, 29) to find the total number of electrons.
The net charge given in Coulombs can then be converted to the number of electrons by using the elementary charge. Dividing the number of electrons corresponding to the net charge by the total number of electrons initially present gives the fraction of electrons removed.
For example, a 50.0 g ball of copper has a net charge of 2.00 μC. The atomic mass of copper is 63.5, and each copper atom has 29 protons (and initially, the same number of electrons for a neutral atom). To find the fraction of electrons removed, we can use this formula: Fraction of electrons removed = (Net Charge in Coulombs / Elementary Charge) / (Total number of initial electrons).