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Find the volume of the solid E whose boundaries are given in rectangular coordinates. x² +y² ≤z≤4−x² −y²,x≥0,y≥0.

A. 2π
B. 4π
C. 8π
D. 16π

User Sponce
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1 Answer

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Final answer:

To find the volume of the solid E, we need to integrate over the given boundaries in rectangular coordinates and convert them to cylindrical coordinates. The volume of solid E is equal to the evaluated integral ∫∫ (2 - r²) rdrdθ over the region 0 ≤ r ≤ √(2) and 0 ≤ θ ≤ 2π. The answer is 2π.

Step-by-step explanation:

To find the volume of the solid E, we need to integrate over the given boundaries in rectangular coordinates. The given boundaries are x² + y² ≤ z ≤ 4 - x² - y², x ≥ 0, y ≥ 0. We can rewrite these boundaries as follows:

  • x² + y² ≤ z ≤ 4 - (x² + y²)
  • Simplifying further, we get 2(x² + y²) ≤ 4, which simplifies to x² + y² ≤ 2

Now, we can set up the integral for the volume as follows:

  • ∫∫∫ dV = ∫∫∫ dzdydx
  • Using cylindrical coordinates, we have:
  • ∫∫∫ r dzdrdθ
  • Since the volume of a solid E can be represented by the equation x² + y² ≤ 2, we can integrate over the region:
  • 0 ≤ r ≤ √(2) and 0 ≤ θ ≤ 2π
  • Thus, the volume of the solid E is given by:
  • V = ∫∫∫ r dzdrdθ = ∫∫ (2 - r²) rdrdθ

Simplifying the integral and evaluating it over the given region, we can find the volume of solid E. The answer is option A. 2π.

User Scozy
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