Question

calculate the volume of chlorine in dm3 produced if the reaction is conducted at standar temperature and pressure

Answer 1

Tthe volume of chlorine gas at STP, use the ideal gas law with the balanced equation coefficients. For instance, in "
`2HCl \rightarrow H_2 + Cl_2`," 2 moles of HCl yield 22.4 dm³ of
`Cl_2`.

The volume of chlorine gas produced in a chemical reaction at standard temperature and pressure (STP) can be determined using the ideal gas law. At STP, one mole of any gas occupies 22.4 dm³.

For chlorine gas (
`Cl_2`), the balanced chemical equation will indicate the stoichiometry of the reaction. Assuming a balanced equation like "aA + bB → cC + dD," where a, b, c, and d are the coefficients, the volume of chlorine (
`Cl_2`) can be determined based on the coefficients in the reaction.

For example, if the balanced equation is "
`2HCl \rightarrow H_2 + Cl_2`," it implies that two moles of hydrochloric acid (HCl) produce one mole of chlorine gas. Therefore, at STP, the volume of chlorine gas produced would be 22.4 dm³ for every two moles of HCl reacted.

Calculate the moles of chlorine produced based on the balanced equation, and then use the ideal gas law (PV = nRT) to find the volume at STP, where P is pressure (1 atm), V is volume, n is moles, R is the ideal gas constant, and T is temperature (273.15 K at STP).