Question

What angle θ3 does the ray refracted into the water make with the normal to the surface? (Index of refraction of water = 1.33)

Options:
a) 45 degrees
b) 30 degrees
c) 60 degrees
d) 90 degrees

Answer 1

The angle θ3 that the ray refracted into the water makes with the normal to the surface is approximately 33.74 degrees.

Step-by-step explanation:

The angle that the ray refracted into the water makes with the normal to the surface can be calculated using Snell's law:

n1*sin(theta1) = n2*sin(theta2)

Where n1 is the index of refraction of the incident medium, theta1 is the angle of incidence, n2 is the index of refraction of the refracting medium (water in this case), and theta2 is the angle of refraction.

Given that the angle of incidence is 45 degrees and the index of refraction of water is 1.33, we can calculate the angle of refraction using Snell's law:

n1*sin(theta1) = n2*sin(theta2)

1*sin(45) = 1.33*sin(theta2)

sin(theta2) = sin(45)/1.33

theta2 = arcsin(sin(45)/1.33)

theta2 ≈ 33.74 degrees

Therefore, the angle θ3 that the ray refracted into the water makes with the normal to the surface is approximately 33.74 degrees.