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How much of a 14% ethanol fuel mixture should be mixed with 10 gal of 5% ethanol fuel mixture to get a mixture that is 12% ethanol?

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Final answer:

To get a mixture that is 12% ethanol, you need to mix 35 gallons of the 14% ethanol fuel mixture with 10 gallons of the 5% ethanol fuel mixture.

Step-by-step explanation:

To solve this problem, we can set up an equation based on the given information:

Let x be the amount of 14% ethanol fuel mixture needed. The equation is:

(0.14x + 0.05 * 10) / (x + 10) = 0.12

Multiply both sides of the equation by (x + 10) to eliminate the denominator:

0.14x + 0.05 * 10 = 0.12 * (x + 10)

Simplify the equation:

0.14x + 0.5 = 0.12x + 1.2

Combine like terms:

0.02x = 0.7

Divide both sides of the equation by 0.02:

x = 35

Therefore, you need 35 gallons of the 14% ethanol fuel mixture.

User Rkstar
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