The value of dx/dt when x = 3 and dy/dt = −2 is 1.2.
We can solve this problem using implicit differentiation:
Start with the given equation: xy = 15
Differentiate both sides of the equation with respect to t:
d/dt (xy) = d/dt (15)
x(dy/dt) + y(dx/dt) = 0
Substitute the given values:
3(-2) + y(dx/dt) = 0
-6 + y(dx/dt) = 0
Solve for dx/dt:
y(dx/dt) = 6
dx/dt = 6 / y
Plug in the value of x:
dx/dt = 6 / (15/3)
dx/dt = 6 / 5
Therefore, the value of dx/dt when x = 3 and dy/dt = −2 is 1.2.