Final answer:
The eigenvalues are λ = -i and the eigenvector is v(x) = e^(-ix).
Step-by-step explanation:
To find the eigenvalues and eigenvectors of the operator −id/dx acting in the vector space of differentiable functions c^1(−∞,∞), we can start by looking for solutions to the equation −id/dx f(x) = λf(x). Let's denote the eigenvalues as λ and the corresponding eigenvectors as v(x).
If we differentiate the eigenvector v(x) with respect to x and substitute into the equation, we get -iv'(x) = λv(x). This is a first-order ordinary differential equation, and its solutions can be written as v(x) = Ce^(-ix), where C is a constant and i is the imaginary unit.
So the eigenvalues are given by λ = -i, and the corresponding eigenvector is v(x) = e^(-ix). Therefore, the correct answer is B) λ = -i, v = e^(-ix).