Question

The Ksp of copper sulfide (CuS) is 8.0 × 10–37. What is the solubility concentration of [Cu2+] in a saturated solution at 25°C?

A) 2.8 × 10^19 M
B) 4.0 × 10^9 M
C) 1.6 × 10^18 M
D) 2.0 × 10^18 M

Answer 1

The solubility concentration of [Cu2+] in a saturated solution of copper sulfide (CuS) is 2.8 × 10⁻¹⁹ M, as calculated from the given Ksp value using the square root of Ksp.

Step-by-step explanation:

The solubility concentration of [Cu2+] in a saturated solution of copper sulfide (CuS) at 25°C can be determined using the Ksp (Solubility Product Constant). The Ksp for CuS is given as 8.0 × 10⁻³⁷. For every one mole of CuS that dissolves, one mole of Cu2+ ions and one mole of S2- ions are produced in solution. Therefore, the solubility of CuS, represented as 's', can be expressed as Ksp = [Cu2+][S2-] = s². Solving for 's', we get s = √(Ksp), which equals √(8.0 × 10⁻³⁷). The result is 2.8 × 10⁻¹⁹ M, which corresponds to option A.