Final answer:
To find the pressure at 11,000 meters depth, use the formula P = ρgh with the given density of seawater. Calculations show that the pressure in kilopascals is approximately 106,945.62 kPa, which is equivalent to 1.055 atm, and 15,507 psi. Therefore, none of the provided options fully matches the calculated pressure, but option A is close.
Step-by-step explanation:
To calculate the pressure at the deepest point in the oceans, we use the formula P = ρgh, where P is the pressure, ρ is the density of seawater, g is the acceleration due to gravity, and h is the depth. We are given a depth (h) of 11,000 meters and a density of seawater (ρ) as 998.2 kg/m³.
Assuming standard gravity (g) as 9.81 m/s², we can calculate the pressure (P) in pascals (Pa) and then convert it into other units such as kilopascals (kPa), atmospheres (atm), and pounds per square inch (psi).
First, we calculate the pressure in pascals (Pa):
P = ρgh = 998.2 kg/m³ × 9.81 m/s² × 11,000 m = 106,945,620 Pa.
To convert to kilopascals, we divide by 1,000 since 1 kPa = 1,000 Pa:
P(kPa) = 106,945.62 kPa.
To convert to atmospheres, we divide by 101,325 since 1 atm = 101,325 Pa:
P(atm) = 1.055 atm (rounded to three decimal places).
To convert to psi, we use the fact that 1 psi = 6,894.76 Pa:
P(psi) = 15,507 psi (rounded to two decimal places).
Therefore, none of the options provided matches the calculated pressure exactly. However, if the pressure is rounded less precisely, option A could be considered close but it is not the accurate answer.
It's important to note the assumption of constant density of seawater is an approximation since the density increases slightly with depth due to the increase in pressure. A more accurate calculation would consider the variation of the density of seawater with depth, but this is beyond the scope of the question.