Final answer:
It involves balancing the combustion equations for propane (C3H6), pentane (C5H12), methanol (CH3OH), and sucrose (C12H22O11).
Step-by-step explanation:
It asks to complete and balance the equation for the complete combustion of four different hydrocarbons and one alcohol. Here are the balanced equations for each:
- For C3H6 (propane), the balanced combustion reaction is: 2C3H6 + 9O2 → 6CO2 + 6H2O.
- For C5H12 (pentane), the balanced equation is: C5H12 + 8O2 → 5CO2 + 6H2O.
- For CH3OH (methanol), the balanced equation is: 2CH3OH + 3O2 → 2CO2 + 4H2O.
- For C12H22O11 (sucrose), the balanced equation is: C12H22O11 + 12O2 → 12CO2 + 11H2O.
These balanced equations represent the reaction between these compounds and oxygen resulting in carbon dioxide and water as the combustion products.