Question

Let A1 and A2 be the events that a person is left eye dominant. What is P(A1 ∩ A2)?

a) 0
b) 1
c) 0.5
d) Cannot be determined

Answer 1

The probability of the intersection of two events representing left eye dominance is 0. The correct option is a.

Step-by-step explanation:

Let's denote the events A1 = a person is left eye dominant and A2 = a person is left eye dominant. The intersection of two events, denoted A1 ∩ A2, represents the event that both A1 and A2 occur simultaneously. Since being left eye dominant is a characteristic that a person either has or doesn't have, and assuming that being left eye dominant is independent of being left eye dominant, the probability of A1 ∩ A2 is 0. In other words, P(A1 ∩ A2) = 0.

Hence, a is the correct option.