Final answer:
The question requires calculating the period of a machine with a natural frequency of 45 Hz, found by taking the inverse of the frequency, resulting in a period of 1/45 seconds.
Step-by-step explanation:
The question is asking to calculate the period of the machine given that its measured natural frequency is 45 Hz (the question assumes Hertz as the unit for frequency, though it's not explicitly stated). The natural frequency is defined as the frequency at which a system oscillates when it undergoes free vibration without a driving force or damping, but in some contexts, it can also refer to the oscillation under forced vibration with damping.
The period of oscillation is the inverse of the frequency, which can be calculated using the formula Period (T) = 1 / Frequency (f). Therefore, to find the period of the machine, we use the given natural frequency of 45 Hz and find that the period T is 1/45 seconds.