Question

Let f(x,y) = xeˣ²⁻ʸ and p = (13,169).

a) f(13,169) = 0
b) f(13,169) = 1
c) f(13,169) = 13
d) f(13,169) = 169

Answer 1

After evaluating the function f(x,y) with the given values, the correct answer is f (13,169) = 13, as exponentiation by zero yields one, and multiplying by 13 results in 13.

Step-by-step explanation:

The student is asking which value is correct for f (13,169) when f(x,y) = xe⁴²⁹⁺ʹ and p = (13,169). To solve this, we must plug in the values of x and y into the function:

f (13,169) = 13 * e¹³²⁹⁶⁹

Since e¹³²⁹⁶⁹ is e¹⁰⁰⁸⁴ʹ (which equals e⁰ = 1), we can simplify the function to:

f(13,169) = 13 * 1

Therefore, the correct value is f (13,169) = 13.