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at what speed v2 will the great sandini emerge from the end of the gun barrel? express your answer in meters per second to three significant figures.

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Final answer:

The muzzle velocity of the bullet when it emerges from the end of the gun barrel is 502.2 m/s, calculated using the kinematic equation v = u + at with a given acceleration of 6.20×105 m/s² for 8.10×10-4 s.

Step-by-step explanation:

To calculate the muzzle velocity of a bullet, we will use the kinematic equation which relates final velocity, initial velocity, acceleration, and time.

Given that a bullet is accelerated from rest in the firing chamber to the end of the barrel at an average acceleration of 6.20×105 m/s² for a duration of 8.10×10-4 s, we can use the equation:

v = u + at

where:

  • v is the final velocity (muzzle velocity),
  • u is the initial velocity (which is 0 m/s since the bullet starts from rest),
  • a is the acceleration (6.20×105 m/s²), and
  • t is the time (8.10×10-4 s).

Substituting the given values:

v = 0 + (6.20×105 m/s²) × (8.10×10-4 s)

v = 502.2 m/s

Therefore, the muzzle velocity of the bullet when it emerges from the end of the gun barrel is 502.2 m/s, to three significant figures.

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