Final answer:
The particle crosses the origin at t = 2.0 seconds. The displacement of the particle between t = 3.0 s and t = 6.0 s is -6.0 meters. These answers address the motion of the particle and its change in position over time.
Step-by-step explanation:
The question asks about the motion of a particle under various conditions, including its velocity, acceleration, and position functions over time. Let's address each given situation:
27. Particle Crossing the Origin
To determine when the particle crosses the origin (x=0), set the position function x(t) = 4.0 - 2.0t to zero and solve for t:
4.0 - 2.0t = 0
2.0t = 4.0
t = 2.0 seconds
The particle crosses the origin at t = 2.0 seconds.
27. Displacement of the Particle
The displacement between two times is the difference in position. Calculate the positions at t = 3.0 s and t = 6.0 s, then subtract:
x(3.0 s) = 4.0 - 2.0(3.0) = -2.0 m
x(6.0 s) = 4.0 - 2.0(6.0) = -8.0 m
Displacement = x(6.0 s) - x(3.0 s) = -8.0 m - (-2.0 m) = -6.0 m
The displacement of the particle between t = 3.0 s and t = 6.0 s is -6.0 meters.