Final answer:
The x-coordinate of the center of mass of a lamina can be found using the formula x-bar = ∫x dm / ∫dm, where dm represents the mass element and x represents the position along the x-axis. By expressing dm as λ(dx), the formula becomes x-bar = ∫x λ(dx) / ∫ λ(dx).
Step-by-step explanation:
The x-coordinate of the center of mass, denoted as x-bar, is given by the formula x-bar = ∫x dm / ∫dm. This formula represents the average position of the mass along the x-axis. To use this formula, we need to integrate the position variable x with respect to the mass element dm. In this case, we can express dm as λ(dx), where λ is the linear mass density of the rod and dx is the infinitesimally small length element along the rod. After integrating, we have x-bar = ∫x λ(dx) / ∫ λ(dx), where we integrate from the initial position x = 0 to the final position x = L.