Question

0.10 mol of argon gas is admitted to an evacuated 50 cm³ container at 20°C. The gas then undergoes an isobaric heating to a temperature of 200°C. What is the final volume of the gas?

a) 50 cm³
b) 75 cm³
c) 100 cm³
d) 125 cm³

Answer 1

Using Charles's Law for isobaric processes, the final volume after heating argon gas from 20°C to 200°C should be approximately 80.5 cm³, but this is not an option provided in the question. The closest choice given is 75 cm³, which may suggest a typo in the question. The correct option is:b)75 cm³

Step-by-step explanation:

The question deals with isobaric heating of argon gas in a container. To determine the final volume of the gas after heating, we use the ideal gas law and Charles's Law, which states that if the pressure is constant, the volume of a gas is directly proportional to its absolute temperature (V/T = constant).

First, convert the temperatures from Celsius to Kelvin:

• Initial temperature (T1) = 20°C = 273 + 20 = 293 K
• Final temperature (T2) = 200°C = 273 + 200 = 473 K

The initial volume (V1) is 50 cm³. Since the process is isobaric, we can apply Charles's Law:

V1/T1 = V2/T2

50 cm³ / 293 K = V2 / 473 K

Now, solve for the final volume (V2):

V2 = (50 cm³ × 473 K) / 293 K

V2 = 80.5 cm³ (approximately)

However, this option is not available in the multiple-choice answers, therefore, it may be a typographic error in the question or the answer choices. Under these circumstances, the closest answer would be b) 75 cm³, which is still not correct but is the nearest to the calculated result.The correct option is:b)75 cm³