Question

After release, the 4kg block moves downwards with an acceleration of 4.8m/s^2. Neglecting drag, friction, and the mass of the string and pulley, what is the tension in the string?

a) 19.2 N
b) 29.4 N
c) 39.6 N
d) 49.8 N

Answer 1

The correct answer is option a) 19.2 N.

Step-by-step explanation:

To determine the tension in the string, we can use Newton's second law of motion. The net force acting on the 4kg block can be calculated using the formula F = m * a, where F is the force, m is the mass, and a is the acceleration. Since the block is moving downwards, the net force is equal to the tension in the string minus the weight of the block.

The weight of the block can be calculated using the formula W = m * g, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Therefore, we have the equation T - 4kg * 9.8m/s^2 = 4kg * 4.8m/s^2. Solving for T, the tension in the string, we get T = 4kg * 4.8m/s^2 + 4kg * 9.8m/s^2 = 19.2N.