Question

A solution with 0.495 mol of pyridinium fluoride and enough water to make 1.00 L.

What is the molarity of the pyridinium fluoride solution?

A) 0.495 M
B) 0.990 M
C) 1.00 M
D) 2.00 M

Answer 1

The molarity of the pyridinium fluoride solution is 0.495 M.

Step-by-step explanation:

The molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate the molarity of the pyridinium fluoride solution, we need to determine the number of moles of pyridinium fluoride and the volume of the solution. The solution has 0.495 mol of pyridinium fluoride and a final volume of 1.00 L. Therefore, the molarity of the pyridinium fluoride solution is:

Molarity = moles of solute / volume of solution = 0.495 mol / 1.00 L = 0.495 M