Question

Y=x2+6x+7 Which function has the same solutions as the given function?

y=(x+3)2−2

y=(x+6)2−7

y=(x+4)2+3
y=(x+7)2+6

urgent need answers stat!!!!!

Answer 1

Answer: The first one, y = (x + 3)² - 2.

Explanation:

To solve this question, we can see that the given function and the answer options are in different equation forms. The given is in standard, but the answer options are in vertex. We will change the given function into vertex form. This is also known as completing the square.

y = x² + 6x + 7

y = (x² + 6x) + 7

y = (x² + 6x +
`(6)/(2) ^2` -
`(6)/(2) ^2`) + 7

y = (x² + 6x + 9) + 7 - 9

y = (x² + 6x + 9) - 2

y = (x + 3)² - 2

Now, we can see the correct answer option is the first one;

"y=(x+3)2−2"