Question

Two charges are placed as shown in (Figure 1) with q1 = 1.2 μC, q2 = -3.3 μC, and d = 0.11 m.What is the net force between the charges?

A) 2.64 N
B) 3.96 N
C) 4.53 N
D) 6.62 N

Answer 1

The correct answer is not among the provided options. The calculated net force is approximately 2940.52 N, which does not match any of the given choices.

This correct answer is none of the above.

Step-by-step explanation:

To find the net force between the two charges, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is given by:

F=k ∣q1⋅q2∣/r2

where:

F is the force between the charges,

k is Coulomb's constant, approximately

8.99×109 N m2 /C2,

q1 and q2 are the magnitudes of the two charges, r is the separation between the charges.

In this case, q1 = 1.2 μC, q2 = −3.3 μC, and d=0.11 m.

First, convert the charges to coulombs:

q1 =1.2 μC×10−6 C=1.2×10−6C

q2 =−3.3 μC×10−6 C=−3.3×10−6C

Now, substitute these values into Coulomb's Law:

F=(8.99×109 ) ∣1.2×10−6 C⋅(−3.3×10−6C)∣ / (0.11 m)2

Calculate the force:

F≈(8.99×109 )3.96×10−12/ 0.0121

F≈2940.52 N

The net force between the charges is approximately 2940.52 N.

However, this answer does not match any of the provided options. It's possible there might be an error in the given options or in the values provided for the charges or separation distance. Please double-check the information and calculations.

This correct answer is none of the above.